counting money

In the previous post we have discussed about Negative and Positive Numbers and In today's session we are going to discuss about counting money.
When we talk about the transactions in earlier times, we recall the barter system of transaction. In this system we exchange the articles as per our requirements. Later the transaction of the objects was converted into the standard form, where the cost of each item was calculated in terms of the currency of each country. We call this currency as money.  Let us talk about counting money, where we have the standard unit of money in India as Rupees.
In case of Rupees, we say that 1 rupee is equal to 100 Paisa.
Now we say that the money can be converted into paisa in the following ways:
If we talk about converting rupees into paisa we say that the rupees will be multiplied into paisa by multiplying it by 100. So if we need to convert 3 Rupees into paisa, we write 3 Rupees = 3 * 100 = 300 Paisa
Similarly we say that Paisa will be converted into rupees by dividing paisa by 100. So we say that we proceed as follows:
400 Paisa = 400 / 100 = 4 Rupees
655 Paisa = 655 / 100 = 6 Rupees and 55 Paisa or we write it as Rs 6.55
If the amount of paisa is less than 100 paisa, we say that the money in rupees will be expressed as follows:
60 paisa can be written as Rs 0. 60 or we write as 0 Rupees and 60 Paisa.
 We can take help math online tutor to learn about how to Solve Systems of Equations. We can also download the icse board papers from the internet to get the detailed idea of the pattern of question paper. This helps the child to prepare for the upcoming examinations.

Negative and Positive Numbers

In the previous post we have discussed about Functions and Relations and In today's session we are going to discuss about Negative and Positive Numbers.

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Integer numbers extend from negative infinite to positive infinite numbers. Now we will look at Positive And Negative Number.

If we draw a number line representing the integer numbers and observe that numbers representing on the left side of the number line are all negative numbers and the numbers represented on the right side of the number line are positive numbers. Now if we look at the Positive and negative numbers, we observe that every positive number has its reverse and if we add the positive number and its reverse, we get the result 0. So we call 0 as the additive identity. We can express this relation as follows:

Let the number is 5, its negative number is (-5). Now if we add 5 and -5, we get:

  = 5 + (-5) = 0.

All mathematical operations can be performed on positive and negative numbers. Even positive numbers can be compared.

While comparing numbers we must remember the following rules:

1.    If we compare the positive number with number zero, we say all positive numbers are always greater than 0.

2.    If we compare a negative number with number 0, then we conclude that all negative numbers are always less than zero.

3.     If positive and negative numbers are compared, we conclude that all negative numbers are always smaller than positive numbers.

4.   More we move to the left of the number line, the numbers goes on decreasing. On another hand, if we go on moving to the right of the number line, we come to the conclusion that the number increases.

Natural Elements can be studied in books of cbse class 10 sample papers.

Functions and Relations

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Hello friends, in this blog we will understand the concept of Relations and Functions. Here we will discuss relation and function one by one. First we will talk about relation. Suppose we have given two sets I and J then relation 'R' can be defined from set 'I' to set 'J', is a subset of I * J. It is denoted in two forms that are given as:

List form

Tabular form

There are different types of relation which are shown below.

Ø Reflexive Relation

Ø Symmetric Relation

Ø Transitive Relation

Now we will see small introduction about all these given relations. First we will discuss reflexive relation.

Reflexive relation is a relation such that every element is related to itself. For example: (I, I) Є R for all i Є I.

Symmetric relation: Any relation 'R' is called as symmetric relation if (i, j) Є R = (k, i) Є R for all i, j Є I.

Transitive relation: Any relation 'r' is said to be a transitive relation if (i, j) Є R and (j, k) Є R => (i, k) Є R for all i, j, k Є I.

Now we will understand the concept of function.

Function is a group of ordered pair in which two terms present in pair must be different. Now we will discuss different types of function which are given as:

Ø One – one function

Ø Onto function

Ø Into function

Let’s have small introduction about all given functions. First we will understand the concept of one – one function.

One – one function - A function f: I → J is called as one – one function if every input term 'I' has different image in 'J'. So we can also write it as:

f : I → J is one – one if value of 'I' not equal to 'J'. (I ᚌ J) → f (I) ᚌf (J) for all IJ Ԑ I.

Molar Mass of Water is the mass of one mole of H₂O. Cbse sample paper for class x is helpful for preparation of board exams. In the next session we will discuss about Negative and Positive Numbers. 

algebra word problem solver free

In the previous post we have discussed about how to do pre algebra and In today's session we are going to discuss about algebra word problem solver free. We come across many real life problems, which are solved by the help of forming the equation. These equations are formed by considering the variables and then forming the required equations based on the given relations.

We have Algebra Word Problem Solver Free online which can be used to understand the concept how the relations are expressed in the form of the expressions and how the equations are formed. We also use the online Algebra Word problem solver to learn how the formed equation can be solved. The equation solution simply means to find the value of the variable. The value of the variable which we get by solving the equation is the solution to the given equation. This value when placed in the place of the variable in the given equation, will satisfy the equation .

There are different methods used to solve the algebraic equations. One of the very common method of solving the equation is by the Hit and Trial method. By Hit and Trial method we mean that the different values are placed in place of the variable in the given equation. We need to search the values which when placed in the equation, will satisfy the equation. Let's us look at the following problem:

Find the number which when added to 5 results 9.

Here let's us assume that the number is x. We form the equation as follows :

X + 5 = 9.

Now we say that let the value of x = 1, so on putting the value of x = 1, we get :

1 + 5 <> 9.

So it does not satisfy the equation

Similarly we go on trying different values and finally if x = 4, then

4 + 5 = 9

So, x = 4 is the solution to the equation.

Radioactive Isotopes is one of the topic of Cbse Paper For Class 9.  

how to do pre algebra

In the previous post we have discussed about how many hours in a year and In today's session we are going to discuss about how to do pre algebra. Pre algebra can be considered as a part of algebra which contains all basic concept of algebra. In school, the study of pre algebra starts from grade 5th that continue to grade 8th. The basic reason behind the study of pre algebra is to make the students ready for handling the mathematical algebra. Sometime students face trouble while they are going to solve algebraic equations. The basic reason behind this problem is that students are not able to clearly understand the concept of algebra, at that pre algebra play their role to make the students ready to face the problem and find the solution of their problem on its own.
Here in this section discussion being held on the topic of how to do pre algebra. As the name of topic describes that how a student is being able to solve a problem of pre algebraic equations. To deal with this topic students need to cover some topic that are study the fundamental of number system and their types like integer, fractional number or the concept of factor of number and properties of operations like commutative, distributive and so on. There are so many other concept that also helps in understanding the concept of pre algebra and after that algebra like:
I ) Understand the order of addend means x + ( y + z ) = (x + y ) + z.
II ) Adding any number to zero gives the same output number.
III ) If two variables ate same to each other then their other tasks are also same.

The concept of Rationalizing the Denominator is a process which is perform when we want to convert root of denominator into their numerator value. The 10th cbse sample paper is a similar kind of board paper that helps the students to evaluate their exam preparation.  

how many hours in a year

The hour and year both can be consider as a unit of time. The Hour which is sometime can be referred by hr. It is a unit of time which is equal to the 1 / 24 part of a day, 60 minutes and 3600 second. Day, minutes and seconds are also a unit of time. Normally, time is a important part of life, on the basis of time we decide our lots of work in a real world life. Generally time is measured on a pattern of two twelve hour segments of a day. The first segment of is denoted by AM and second segment is denoted by PM.

On the other side Year can be describe as a time of the earth which is taken to make one move around the sun. According to various scientist’s, a year is equal to the 365 days and 6 hours but remaining 6 hours can’t be calculated in a year. After each 4 year, one year become the year of 366 days because 6 hours of each year make a one day which is added into every 4thyear. Every 4^th year is equal to 366 days popularly known as leap year.

Here in this section discussion held on how many hours in a year. After discussing about hour and year we can easily elaborate the answer of above question. As we know that one year is equal to 365 days and one day is equal to 24 hours. So, we can easily calculate that how many hours in a year in the below given manner.

Hours in a year = 24 * 365 = 8760 hours

If we want to calculate hours in a leap year then it could be 8784 hours in a year.

In chemistry, the transition metal are the most abundant elements and sometime called as Representative Elements. For IIT entrance exam, iit sample papers helps the students to perform better in exams.

 

radical calculator

In the previous post we have discussed about How to Graph an Equation and In today's session we are going to discuss about radical calculator. In mathematics, we will see many types of expression such as polynomial expression. Here we will discuss the concept of radical calculator. An expression which is having root values, such as square roots, cube roots are known as radicals. For example: √ (r + s), and 3√ (r + s). The value of 2 means square root, 3 means cube root and so on. Radicals are denoted by the symbol '√'. Now we will see radical calculator.

Radical calculator can be defined as a online machine which is used to add the multiple values within a seconds. Now we will understand some steps that are used to solve the radical values.

Step 1: Let we have to add two radical values then put two root values in two text box.

Step 2: Then enter solve button to get desired result. Now we will discuss it with the help of example:

For example: Let we have to add two unlike radicals. 2 √7 + 4 √9 + √7 + 5 √9.

Solution: Here we need to see some steps so that we can easily add the radical values.

Step 1: Given radical expression is 2 √7 + 4 √9 + √7 + 5 √9, Now we have to add radical values given in the expression.

Step 2: Now we have to find the common term if present in the given radical expression.

In this expression two pairs are same. So we can write them as:

= 2 √7 + 4 √9 + √7 + 5 √9,

= 2 √7 + √7 + 4 √9 + 5 √9,

Now find common term in expression. (know more about radical calculator, here)

= (2 + 1) √7 + (4 + 5) √9, Now add the radicals we get. On adding these values we get;

= 3 √7 + 9 √9. In this way we can easily add radical.

Relative Standard Deviation can be defined as a measure of precision. Mostly it is also known as coefficient of variation used to find the percentage.

To achieve good score in 10 th board then please prepare 10th maths question paper.